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Stoichiometry Review Answers Using the following equation:

2 NaOH + H2SO4  2 H2O + Na2SO4 1. How many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid? 355.2 g Na2SO4

2. How many grams of sodium hydroxide is needed to produce 64.3 dm3 of water vapor? 114.7 g NaOH

3. If you begin with 8 x 1023 molecules of sulfuric acid and react it with excess sodium hydroxide how many grams of Na2SO4 will be formed? 188.77 g Na2SO4

4. How many grams of water will be produced if you react 3 mol of sulfuric acid with sufficient sodium hydroxide? 108.13 g H2O

5. If you begin with 6 pounds of Na (2.2 lb per kg) how many molecules of Sodium Sulfate will be produced? 2.05 x 1025 molec Na2SO4

Use the following equation to solve the following:

Pb(SO4)2 + 4 LiNO3  Pb(NO3)4 + 2 Li2SO4 6. How many grams of lithium nitrate will be needed to make 250 grams of lithium sulfate, assuming that you have an adequate amount of lead (IV) sulfate to do the reaction? 313.55 g LiNO3

7. How many mol of lead nitrate would be produced if you began with 60 grams of lithium nitrate and reacted that with excess lead sulfate? 0.22 mol PbNO3

8.) 5.3 x 1023 molecules of lead sulfate will react with excess lithium nitrate. How many cubic decimeters of lithium sulfate will be produced from this reaction? (Lithium sulfate is rarely found as a gas but lets just assume it will be for the sake of this problem.) 39.44 dm3 LiSO4

9. How many grams of lead nitrate will be produced if you react 80 grams of lead sulfate with excess lithium nitrate? 91.2 g PbNO3

Answer number 10 and 11 without an equation. 10. How many moles are there in 6.02 x 1023 atoms of a substance? 1 11. How many moles are there in 22.4 dm3 of a substance? 1

5. What is the empirical and molecular formula for a compound consisting of 40.00% C, 6.72% H, 53.29% O. The mass of the molecular formula is 180 g/mol. Empirical: CH2O Molecular: C6H12O6 6. What is the percent by mass of carbon in CH4? 74.8% Carbon

7. Using the above reaction determine the mass of oxygen gas needed to produce 450 dm3 of CO2? 1285.4 g O2

Use this equation for the following problem:

CuCl2 + 2 NaNO3 

Cu(NO3)2 + 2 NaCl

a) If 15 grams of copper (II) chloride (CuCl2) react with 20.0 grams of sodium nitrate (NaNO3), how much sodium chloride (NaCl) can be formed? About 13 g of NaCl b) What is the name of the limiting reagent? ________CuCl2__________ c) How much of the excess reagent is left over in this reaction? About 1 gram d) If 11.3 grams of sodium chloride are formed in this reaction in a lab, what is the percent yield of this reaction compared to the theoretical value you calculated?

86.9%

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