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K.S ACADEMY, SALEM-PG TRB ANSWER KEY

PG TRB ,ENG & POLYTECHNIC TRB & TNSET COACHING CENTRE FOR PHYSICS CDE-2017 PHYSICS TENTATIVE KEY PUBLISHED ON 02-07-2017 PG TRB –PHYSICS(2017) BOOKLET SERIES C ANSWER KEY S.NO 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17

OPTION A D A B A A C C C D D B C B A B B

18 19 20 21 22

B C D C C

23 24 25 26

B B A C

27 28

* A

29 30

D C

31

A

32

D

ANSWER μ-meson T0 T vs C Become Maxwell-Boltzmann distribution 2.18 K 2.7 X 1017 J (c) only The passenger on the west side looks up first 0.94 C Ampere’s law 80 G1H1 = G2H2 𝑚𝑥̈ + 𝑘𝑥 = 0 (a) is true and (b) is false Angular displacement and angular momentum ½ KT 𝑞3 (𝑞1 + 𝑞2 ) 𝜋𝜀0 𝑑2 ∇. 𝐴 = 0 0.8 metre 1.41 m0C2 Coloumb energy Even – even nuclei will have non-spherical shape

KALVIKURAL Even protons and even neutrons Proton follows the spiral path U235 The electron in the normal state loss their ability to transfer heat because of their coupling to the cooper pairs Data(Bohr magneton value is wrong) The flux passing through the superconductor is quantized in units of

ℎ𝑐 𝑒

314𝐴° 𝑖 2 ħ2 𝜕 2 2𝑚 𝜕𝑥 2 1 𝐶= 2√𝑎 In harmonic perturbation the condition Ef = Ei - ħω implies that the system absorb a photon of energy ħω

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K.S ACADEMY, SALEM-PG TRB ANSWER KEY 33 34 35

A C A

36 37

A D

38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62

A A D D D D A D D A B A A C A B D D B D D C C D B

(a)And (c) ½ 𝜋 2 ħ2 𝐿2 G.M counter The spins of the neutron and proton in the ground state of deuteron are anti-parallel 14 14 − 6𝐶 → 7𝑁 + 𝑒 + 𝜈̅𝑒 𝐴̅𝐵̅ + 𝐵̅𝐶̅ + 𝐶̅ 𝐴̅ No stable state 𝑖ħ𝐿𝑍 Nuclear force is saturated Aage bohr Dynode Superheated liquid Multiplying by 2 and dividing by 2 respectively A+B 15.9 kΩ (A)=E1H s = 1 ; z = 1 ; cy = 1 3.58 cm; 9 cm Anode resistance MOV B,C 16 bit Refer diagram (NOT AND OR) 0.5 -1 2.33 X 105m/s 90° Statement (a) and (c) are correct and b is wrong Statement (a) and (b) are correct and (c) is wrong Single frequency and same phase cos 𝛹 sin 𝛹 0 [−sin 𝛹 cos 𝛹 0] 0 0 1

KALVIKURAL 63

C

64 65

B C

66 67 68 69 70 71

B C B C B D

72 73 74 75 76

B D D C B

∫ 𝐿 𝑑𝑡 𝑓𝑟𝑜𝑚 𝑡𝑖𝑚𝑒 𝑡1 𝑎𝑛𝑑 𝑡2 𝑖𝑠 𝑒𝑥𝑡𝑟𝑒𝑚𝑢𝑚

(iv) (iii) (ii) (i) 𝑃𝜑 2 𝜕𝑉 − 2 3 𝑚𝑟 sin 𝜃 𝜕𝜃 0.267 Ev 3 2 ppm 10-6 Ev 1.046 ⃗⃗⃗⃗⃗ −𝑟 𝑟3 0 Unimodular Both unitary and hermitian A2 = A No change in entropy and volume at constant temperature and pressure

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K.S ACADEMY, SALEM-PG TRB ANSWER KEY 77 78

D B

79 80 81 82 83 84 85 86 87 88 89 90

D A C B D A A A B A C D

91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106

B A A D D B D D D A D D B C B A

107 108

C D

109 110

B C

Amorphous thin films of Be, Bi and Fe show superconductivity In all super conductors, the entropy increases markedly on cooling below critical temperature 3/2 (iv) (iii) (i) (ii) Large,zero C,I3 (Ψ̇ + φ̇ cos θ) (a),(b) and (c) (iii) (iv) (i) (ii) 0 IB = IC & IA = 0 Spin-lattice relaxation Ehrenfest’s theorem Anisotropy energy the extent of overlap of wave functions ψ1 and ψ2 corresponding to the two atoms 7 and 5 λ3 - 6λ2 + 9λ -4 = 0 Rank of a matrix varies under elementary operation -1 Does not have any degenerate eigen value 3 X 10-3 Wm-2 (A ) and (B) Twice Water 310.2 CM-1 Every group is isomorphic to itself 36 0.02 (A) (B) and (C) are correct 𝑦 = 2𝑥 + 0 𝜕2𝐺 𝜕𝐺 𝜕𝐺 − 2𝑥 + 2𝑡 =0 2 𝜕𝑥 𝜕𝑥 𝜕𝑡 Statement (a) and (b) are correct and (c) is wrong 4 4 1 5 4𝐶 ( ) ( ) 5 5 Statement (a) is correct (b) and (c) are wrong All are correct statement

KALVIKURAL In our institute we provide large number of numerical problems , because students face difficulties in solving numerical and I strongly recommend to solve problem in slip test questions so our students solve many of the problems asked in the TRB exam. 1. One our Student Reg no:17PG14040664 TRB-2017 MARK(74 OUT OF 110) Expected cut off for PG TRB 2017 (physics) is 77-88 OUT OF 150 POLYTECHNIC TRB-2017 CLASS STARTS ON 8TH JULY Next batch PG TRB admission starts from December 2017 TRB BOARD ANSWER KEY IS FINAL ONE

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