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X.rWhat are the main cbmponents of culvert? (Nor./Dec 2012) I . Abutments 2. Wing walls
3. Arch
.\
2. Define tead. (Nov/Dec 2012)
tt the crow.flying horizontar distance frcm the centre of borrow pit to the centre of at site. i.e centre of the area of excavation to the centre ofplaced earth.
Ine lrtnwork ",^ e,!:1o
lift. (Nov/Dec 2012) Lift is the distance though which the exoavaied soil is lifted
3. Define deoth.
beycrnd a certain specified
4. What are faciors to }e colsidercrl in design of septic tank? The following factors should be rcken inro cousiJeration: - Material shculd be wat:r proofand corrosion iesislaot.
. . . .
Natural ventilation provided should be adequate A manhoie should bp piovided tb permit inipection and cleaning. Baffles should.be limited to one at the inlet and one at the outlet. The escape ofgas and slu,lge tg effiuent pipe ,h"uld ;.'",r;id;.
5; What are the.methods of measurements of earthwork? The work shall be measured as given below
.
Eaci: dinension shallmeasu:ed uearest to 0.01
" . 6,
Area shall be worked orrt nealest to U.Ul
Volume shall be worked oui nearest to 0.Cl m3
Write the formula for Mid ordinaie rule and prismoidat formula Rule.
Mid sectional area method Q = (Bdm+ sdm)
\}'here,
B-
Forntation ..vidth
S
.- Side slopes
d1
-- ivlean clepth
.
'.
L - Length of the section Prismoidal fo r.inula nrie:
t t
!_
Ei
nrl
,
Q: L/5(Ai +A2+4Am) A1
=Bdl
+ sdi2
A2=8r12+
SdZ2
t
5d,f
Ap
-- Bd61
a
dm= (dt+dz)/z
t
rl
r l
i !
i7, Calculate the qua[ty ofearthwork for the construction ofan approach road 'length lKm, = I width of fo.rnation = lo m Height of ernbankmerrt = 60 crn Sidc slope
:
l:2
, Solution:
F
!l
I I ;
Quadiry of earth wo.d< = L (Bd+Sd2) B=1(tcm;d=0.60m;S=2 Quantity of earth work = 1000 x (1U x 0.60) +2 x 0.5C x 0.60 = 6720 cu.m $. Briefly explain about Out to Out and in to in mcthod.
method is most practicable under all circumstances and thc P.W.D tbr computing the quartities of various iterns.
, This ,9,
Biiefly explain abo.ui bay method.
This metiroC is useid and is generally followed in case of builciings havirg several bays. Tire cost of the typical bay is worked out and is then multiplied by ,rhe number of ba;vs in that buiiding. The extra cost for the end walis and diffetence in ftarning, if tlrere is any, should be r,ade, so as to arive at the correct cost 10. Workout thc quality of stone rnetal required for 2Km.Length for: wearing coat of 4m rvide road. The thickness cfthe rnctal road requir.ed is l2cr.r loose.
a
Sotution Qualliy of meial = 1X
2X 1000X4X0.12=960.00cun
It:An approach ruad 2Km.long is to be construcled. nidtblials iLquireai.e.stonemetalan.1bricks.Dataisgivenbelow.
Wolk out the
q'.rantitv of
_'
Ittrrral hd widrh = 3.50m Soifing of bricks = I Ocm
Il&rinf
:
:
mat of stone metal 12 cm Solution Quantityofbricks = I x 2 x 1000 x 3.60 x 0.10 =720cu.m
Stone metiil Br iclis
-
= I x 2000 x 3.60 x 0.12 = 864 cu.m
3,60.0r10 Nos
A
cement concrete road (l:2:3) is to be construoted over the existing water bound macadam road .The thickness of slab =l0cm.The length of the ioad is one km and the width 3.60m.Calculate the quality ofcement concrete and the material requhed? 12.
Solrrtiou
Quality ofcement concrete = I x 1000x3.60x0.10.=360cu.m
l3.what
prime cost ? (Nov/dec 2012; Prime cost is the act'.ral cost ofarticles carrying out of rvork eg: water supply fittings. is
l4.what are
Che
at shop and refers to the supply of and not to
fittings? lNoviDee 2011)
Traps: P-trap
Q.trap S-trap Floor traps and Gulll' traps ,Kitchen sink Water clcsets
lS.f,raw the different parts ofculveft (Nov-iDcc 2011) Arch,abutrnent,paxapet *indow
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