Recognize and write identities Evaluate trig functions using identities Simply and rewrite trig expressions
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5217 Fundamental Identities, block 3.notebook
May 02, 2017
Basic Trigonometric Identities Reciprocal Identities Directions: Move each identity piece into its proper location to match.
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Quotient Identities
Pythagorean Identities
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5217 Fundamental Identities, block 3.notebook
May 02, 2017
Pythagorean Identities on Unit Circle EX #1: If you know the basic identity, it’s easy to derive the others.
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Simplify and Factor Expressions EX #2: Use a quotient identity to simplify and rewrite.
EX #3: Use the idea of “decomposing” fractions to simplify and rewrite.
Case #1:
Case #2:
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5217 Fundamental Identities, block 3.notebook
May 02, 2017
EX #4: Factor completely. A.
B.
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C.
D.
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5217 Fundamental Identities, block 3.notebook
May 02, 2017
Simplifying by Expanding and Using Identities EX. #5: Simplify
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EX. #6: Rewrite so expression is NOT in fractional form.
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5217 Fundamental Identities, block 3.notebook
May 02, 2017
Simplifying by Combining Fractions and Using Identities EX #7: Simplify the expression:
Get Common Denominators:
Use Pythagorean Identity to simplify. Feb 27:15 AM
Solving Trigonometric Equations EX #8: Find all values of x in the interval
Technique: 1. Change everything to sine & cosine. 2. Multiply both sides by sin x to clear fraction. 3. Factor 4. Simplify using Pythagorean Identity. 5. Solve using the unit circle:
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5217 Fundamental Identities, block 3.notebook
May 02, 2017
Even, Odd and CoFunctions Cofunctions are complements of some trig function. Namely, angles that are complements add to 90 degrees and have the same trig ratios.
5217 Fundamental Identities, block 3.notebook. 1. May 02, 2017. Nov 410:28 AM. Fundamental. Identities. Feb 26:47 AM. Fundamental Identities. Goals: ⢠Recognize and write identities. ⢠Evaluate trig functions using identities. ⢠Simply and rewrite trig expressions ...
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Jan 29, 2007 - Each case above has one inequality which is easy to see. If. X â Y â Z forms a Markov chain, then, I(X; Z|Y ) = 0. We know that I(X; Z) ⥠0. So, I(X; Z|Y ) ⤠I(X; Z). On the other hand, if X and Z are independent, then I(X; Z)