Calculus 221 worksheet Example 1. dy , given Find dx
Implicit differentiation
(3xy + 7)2 = 6y.
Solution: Take the derivative with respect to x of each side of the equation. d d (3xy + 7)2 = 6y dx dx dy dy 2(3xy + 7)3(x + y) = 6 dx dx dy dy (18x2 y + 42x) + (18xy 2 + 42y) = 6 dx dx dy 2 18x y + 42x − 6 = −(18xy 2 + 42y) dx 18xy 2 + 42y dy =− dx 18x2 y + 42x − 6 3xy 2 + 7y =− 2 . 3x y + 7x − 6 Example 2. dy Find , given dx
y sin(x2 ) = x sin(y 2 ).
Solution: Take the derivative with respect to x of each side of the equation. d d y sin(x2 ) = x sin(y 2 ) dx dx dy dy y cos(x2 )2x + sin(x2 ) = x cos(y 2 )2y + sin(y 2 ) dx dx dy sin(x2 ) − 2xy cos(y 2 ) = sin(y 2 ) − 2xy cos(x2 ) dx sin(y 2 ) − 2xy cos(x2 ) dy = . dx sin(x2 ) − 2xy cos(y 2 ) Example 3. dy Find , given dx
√
xy = 1 + x2 y.
Solution: 1
2
Take the derivative with respect to x of each side of the equation. d√ d (1 + x2 y) xy = dx dx dy dy 1 −1/2 x + y = 2xy + x2 (xy) 2 dx dx dy x dy y + √ = 2xy + x2 √ 2 xy dx 2 xy dx dy y x √ − x2 = 2xy − √ dx 2 xy 2 xy y 2xy − √ 2 xy dy = x dx √ − x2 2 xy =
4(xy)3/2 − y √ . x − 2x2 xy
Exercise 2x − y . x + 3y
1. (3xy + 7)2 = 6y.
2. x3 =
3. xy = cot(xy).
4. x4 + sin y = x3 y 2 .
5. x cos(2x + 3y) = y sin x. 6. Find the tangent line of the curve at the point: x2 −
√
√ 3xy + 2y 2 = 5 at ( 3, 2).
7. Find the tangent line of the curve at the point: x sin 2y = y cos 2x at (π/4, π/2). 8. The line that is normal to the curve x2 + 2xy − 3y 2 = 0 at (1, 1) intersects the curve at what other point? Answer 1.
dy 3xy 2 + 7y = . dx 1 − 3x2 y − 7x
2.
dy 2 − 4x3 − 9x2 y = . dx 3x3 + 1
3.
dy y =− . dx x
4.
dy 3x2 y 2 − 4x3 = . dx cos y − 2x3 y
5.
dy cos(2x + 3y) − y cos x − 2x sin(2x + 3y) = . dx sin x + 3x sin(2x + 3y)
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Program., Ser. B (2009) 117:129â147. DOI 10.1007/s10107-007-0161-1. FULL LENGTH PAPER. Robinson's implicit function theorem and its extensions. A. L. Dontchev · R. T. ... Received: 18 November 2005 / Accepted: 21 June 2006 / Published online: 19 J
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